In Millikan's oil drop experiment an oil drop carrying a charge Q is held stationary by a potential difference
between the plates. To keep a drop of half the radius stationary the potential difference had to be made
. What is the charge on the second drop
Text Solution
Verified by ExpertsThe correct answer is:
B
In balance condition
⇒ ⇒
⇒ ⇒ 
⇒ ⇒
⇒ ⇒ 
⇒ ⇒
⇒ ⇒ Q 2 = Q / 2
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